Sorry Dan, but bad postings don't qualify you for the idiot of the year. I
heard there was some talk of "Virtual idiot of the year", but when they
looked back at all posts, it was a dead heat between all of us. :-)
George Richardson
'57 TR3, TS15559L
(getting ready to paint - and now on the web!)
http://www.merlingroupinc.com/tr3.htm
-----Original Message-----
From: DANMAS <DANMAS@aol.com>
To: gprtech@frontiernet.net <gprtech@frontiernet.net>
Cc: triumphs@autox.team.net <triumphs@autox.team.net>
Date: Sunday, January 04, 1998 4:00 PM
Subject: Re: Spitfire coils - superfluous information
>In a message dated 98-01-03 21:59:16 EST, gprtech@frontiernet.net writes:
>
>> In order to generate the same spark energy (watts) the 12 volt coil would
>> draw only half the current of a 6V coil. Amps times volts equal watts.
>> Moreover, since you're still applying 12 volts to the coil and ballast
in
>> series, half of the power (watts) is wasted in the ballast. This really
a
>> simplistic view, since the ballast is designed to limit the peak
current,
>> and not actually split the voltage, but the current draw fro the same
>energy
>> would be more for the ballasted coil.
>
>George,
>
>Whoops! ya got me. You're right on all counts. My OF synapses misfired a
>couple of times on this one. I mixed my apples and my oranges, didn't I? I
>usually stew a while over my posts before I let them go out, but I sent
that
>one out a little too quickly.
>
>Now that I am in contention for the "idiot of the year" award, let me make
an
>addition to my original post on this subject. I said to measure the voltage
at
>the coil with the key on to determine if you have a ballast resister or
not.
>Silly me, I meant to say "with the engine running." Ohms law is still in
>effect - E=IR. Without I, you don't have E, and the voltage will be the
same
>on both sides of the resister if the points are open.
>
>
>Dan Masters,
>Alcoa, TN
>
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