I don't know which wiring diascratches you are looking at, but the
MkIV/1500 schematics show either a resistor wire or a resistor, not
both. You should be able to measure the primary resistance of the
coil and use a resistor of the "same" resistance. Alternatively, pick
up any resistor for an ignition coil and you will probably be pretty
close to the right value. AFAIK, they vary from 3.0 to 4.2 ohms.
$10 to $12/ohm is OUTRAGEOUS!
HTH,
Donald.
> From: "bschwart@postoffice.pacbell.net"
> <bschwart@postoffice.pacbell.net>
> Date: Wed, 11 Sep 2002 11:39:59 -0400
>
> I just purchased a later model Distributor from a 1500 with the integral
> ignition module on the side to use on my 1970 1300 Spitfire. I am wiring
> the whole car up myself so that isnt a problem. The problem I do see is
> that on the wiring diagrams that I have for the later model Spitfires there
> is a ballast wire AND a drive resistor the drive resistor is $40 which
> seems a little pricey! Can anybody tell me the resistance of this unit or
> if it is the same as the ballast resistor that I will be using instead of
> the ballast wire currently used on the production Spitfires. In other
> words, can I just use two ballast resistors, one for the coil and one for
> the drive? If I know the value I may be able to just buy a 5 watt
> wirewound resistor to use for a whole lot less than $40
> As a side note, just exactly what is the drive resistor used for in this
> application anyway?
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