To be right on the spot you can do the math
The formula is;
R=E/I R= P/|x| R= pL/A
Where R = Resistance
p (Rho) = Resistivity
P = Power, watts
I = Amperage
E = Voltage, volts
L = Conductor length, feet
A = Cross-sectional area, circular mils
This is a little thick but it's the proper way.
-----Original Message-----
From: John Goethert [mailto:john@triumphspitfire.com]
Sent: Friday, February 16, 2001 1:43 PM
To: spitfires@autox.team.net
Subject: Ignition wire question
Does anyone know how much resistance (roughly) ignition wires should have?
I pulled an ORIGINAL set of wires off my '75 parts car and trying to
determine if they are worth keeping.
I know I need new wires but I like the original, green look, and might have
value to an originality nut.
John Goethert
Knoxville, Tennessee
john@triumphspitfire.com
http://www.triumphspitfire.com
76 Spitfire, 71 GT6, 75 Spit parts car, 90 Miata
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