Re: Anti-roll bar stiffness

[Smokerbros@aol.com]

I have it as:

K = ( 500,000D^4) / ( .4244A^2 * B) + ( .2264C^3)

so, for tubular:

K = [(500,000D^4) - (500,000d^4)] / (.4244A^2 * B) + (.2264C^3)

K is pounds per inch of deflection at the end of the bar.
D is bar diameter.
d is inside diameter.
C is length of the arm element that will bend.
A is leverage length of the arms measured perpendicular to the bar
^ indicates the next number is the power

CHD