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OK and you left out that it's the back EMF from the coil, which is
much more than 12 volts, that charges the condenser and so on as you
describe in a series resonant circuit. My bad, I tried to keep it
simple. <br>
<br>
Anyway you look at it a leaky (partial short) or open condenser
degrades the spark and results in rough running. A fully shorted
condenser means there will be no spark at all since that's the same
as the points not opening.<br>
<br>
CR<br>
<br>
<div class="moz-cite-prefix">On 7/24/2019 2:34 AM, PaulHunt73 via
Mgs wrote:<br>
</div>
<blockquote type="cite"
cite="mid:E74F95D5015E4949A0DDD6B1A1A7B4E9@paul">
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<div><font size="2">Not quite right. With the points closed the
condenser is discharged as it is connected across the points.
When they open it charges up, as the coil is discharging. The
current/voltage characteristic of a condenser (aka
capacitor) is 90 degrees out of phase with an inductor i.e.
the coil. This makes it a tuned circuit as in a radio, and an
oscillation is set up, which increases the HT amplitude and
its duration. That's why an engine will always run badly
without a condenser, and may not even run at all, depending on
several other factors.</font></div>
<div> </div>
<div><font size="2">PaulH.</font></div>
<blockquote style="BORDER-LEFT: #000000 2px solid; PADDING-LEFT:
5px; PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
<div style="FONT: 10pt arial">----- Original Message ----- </div>
<div><br>
</div>
Not true, Max. When the points open, the condenser discharges
through the coil in order to perpetuate the spark. Without the
condenser the engine may not even start. Try it some time. <span
class="moz-smiley-s1"><span>:-)</span></span><br>
</blockquote>
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