Subject: Re: [Shop-talk] Inch pounds

From: Jim Franklin via Shop-talk <[email-masked]>
Date: Sun, 24 May 2020 14:35:34 -0400

Maybe they're trying to account for different diameter steering wheels, so that each one will feel the same? 

I would still use the rim of the steering wheel, and figure out a way to hang a lb 12" from the rim. I like inch-lb torque wrenches because they're more accurate at low torque, like for oil pans. 

jim

> On May 24, 2020, at 2:20 PM, Robert Nogueirao via Shop-talk <[email-masked]> wrote:
> 
> Folk I’m  rebuilding a steering box.  The manual says to set the peg thrust adjustment so it takes 12 inch pounds at the rim of the steering wheel to over come the “high spot” or resistance.
> I have always heard of ‘inch pounds’ as a measure of torque. If so, would it not be measured from the center of the steering wheel?  
> Lacking a inch pound torque wrench my plan was to hang a one lbs weight 12 inches from the center of the wheel and make the adjustment until the weight can over come the resistance and falls.
> Is this what you think the author meant?
> Bob Nogueira 
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From: neiljsherry--- via Shop-talk <[email-masked]>
Date: Sun, 24 May 2020 21:15:40 +0100

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That will be a torque - so you can measure as you describe with a 1 pound m=
ass/force at 12" radius - or any other combination that multiplies out the =
same to 12 (12 pounds at 1", 2 pounds at 6" etc)=2E If hanging a weight on,=
 the steering shaft will need to be horizontal - so the angle of the column=
 in the vehicle is unlikely to be suitable=2E You could use a spring balanc=
e=2E

On 24 May 2020 19:20:08 BST, Robert Nogueirao via Shop-talk <shop-talk@aut=
ox=2Eteam=2Enet> wrote:
>Folk I=E2=80=99m  rebuilding a steering box=2E  The manual says to set th=
e peg
>thrust adjustment so it takes 12 inch pounds at the rim of the steering
>wheel to over come the =E2=80=9Chigh spot=E2=80=9D or resistance=2E
>I have always heard of =E2=80=98inch pounds=E2=80=99 as a measure of torq=
ue=2E If so,
>would it not be measured from the center of the steering wheel? =20
>Lacking a inch pound torque wrench my plan was to hang a one lbs weight
>12 inches from the center of the wheel and make the adjustment until
>the weight can over come the resistance and falls=2E
>Bob Nogueira=20
>Shop-talk@autox=2Eteam=2Enet
>Donate: http://www=2Eteam=2Enet/donate=2Ehtml
>Suggested annual donation  $12=2E96
>Archive: http://www=2Eteam=2Enet/pipermail/shop-talk
>http://autox=2Eteam=2Enet/archive
>
>Unsubscribe/Manage:
>http://autox=2Eteam=2Enet/mailman/options/shop-talk/neiljsherry@talktalk=
=2Enet

--=20
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<html><head></head><body>That will be a torque - so you can measure as you =
describe with a 1 pound mass/force at 12" radius - or any other combination=
 that multiplies out the same to 12 (12 pounds at 1", 2 pounds at 6" etc)=
=2E If hanging a weight on, the steering shaft will need to be horizontal -=
 so the angle of the column in the vehicle is unlikely to be suitable=2E Yo=
u could use a spring balance=2E<br><br><div class=3D"gmail_quote">On 24 May=
 2020 19:20:08 BST, Robert Nogueirao via Shop-talk &lt;shop-talk@autox=2Ete=
am=2Enet&gt; wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0pt 0=
pt 0pt 0=2E8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1e=
x;">
<pre class=3D"k9mail">Folk I=E2=80=99m  rebuilding a steering box=2E  The =
manual says to set the peg thrust adjustment so it takes 12 inch pounds at =
the rim of the steering wheel to over come the =E2=80=9Chigh spot=E2=80=9D =
or resistance=2E<br>I have always heard of =E2=80=98inch pounds=E2=80=99 as=
 a measure of torque=2E If so, would it not be measured from the center of =
the steering wheel?  <br>Lacking a inch pound torque wrench my plan was to =
hang a one lbs weight 12 inches from the center of the wheel and make the a=
djustment until the weight can over come the resistance and falls=2E<br>Is =
this what you think the author meant?<br>Bob Nogueira <hr>Shop-talk@autox=
=2Eteam=2Enet<br>Donate: <a href=3D"http://www=2Eteam=2Enet/donate=2Ehtml">=
http://www=2Eteam=2Enet/donate=2Ehtml</a><br>Suggested annual donation  $12=
=2E96<br>Archive: <a href=3D"http://www=2Eteam=2Enet/pipermail/shop-talk">h=
ttp://www=2Eteam=2Enet/pipermail/shop-talk</a> <a href=3D"http://autox=2Ete=
am=2Enet/archive">http://autox=2Eteam=2Enet/archive</a><br><br>Unsubscribe/=
Manage: <a href=3D"http://autox=2Eteam=2Enet/mailman/options/shop-talk/neil=
jsherry@talktalk=2Enet">http://autox=2Eteam=2Enet/mailman/options/shop-talk=
/neiljsherry@talktalk=2Enet</a><br><br></pre></blockquote></div><br>-- <br>=
Sent from my Android device with K-9 Mail=2E Please excuse my brevity=2E</b=
ody></html>
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[email-masked]

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From: Eric Russell via Shop-talk <[email-masked]>
Date: Sun, 24 May 2020 16:20:31 -0400

Maybe a fish scale would give you an approx estimate of 12 lbs pull at 
the rim?

-- 
Eric Russell
Mebane, NC

[email-masked]

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From: neiljsherry--- via Shop-talk <[email-masked]>
Date: Sun, 24 May 2020 21:52:38 +0100

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12 pounds at the rim will be way too much=2E If steering wheel is 15" diame=
ter it will 7=2E5" radius and your 12 pounds will give 90 inch pounds, not =
12!

On 24 May 2020 21:20:31 BST, Eric Russell via Shop-talk <shop-talk@autox=
=2Eteam=2Enet> wrote:
>Maybe a fish scale would give you an approx estimate of 12 lbs pull at=20
>the rim?
>
>> Folk I=E2=80=99m  rebuilding a steering box=2E  The manual says to set =
the peg
>> I have always heard of =E2=80=98inch pounds=E2=80=99 as a measure of to=
rque=2E If so,
>would it not be measured from the center of the steering wheel?
>> Lacking a inch pound torque wrench my plan was to hang a one lbs
>weight 12 inches from the center of the wheel and make the adjustment
>until the weight can over come the resistance and falls=2E
=2Enet

--=20
Sent from my Android device with K-9 Mail=2E Please excuse my brevity=2E
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Content-Transfer-Encoding: quoted-printable

<html><head></head><body>12 pounds at the rim will be way too much=2E If st=
eering wheel is 15" diameter it will 7=2E5" radius and your 12 pounds will =
give 90 inch pounds, not 12!<br><br><div class=3D"gmail_quote">On 24 May 20=
20 21:20:31 BST, Eric Russell via Shop-talk &lt;shop-talk@autox=2Eteam=2Ene=
t&gt; wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0pt 0pt 0pt =
0=2E8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">
<pre class=3D"k9mail">Maybe a fish scale would give you an approx estimate=
 of 12 lbs pull at <br>the rim?<br><br>On 5/24/2020 2:20 PM, Robert Nogueir=
ao via Shop-talk wrote:<br><blockquote class=3D"gmail_quote" style=3D"margi=
n: 0pt 0pt 1ex 0=2E8ex; border-left: 1px solid #729fcf; padding-left: 1ex;"=
>Folk I=E2=80=99m  rebuilding a steering box=2E  The manual says to set the=
 peg thrust adjustment so it takes 12 inch pounds at the rim of the steerin=
g wheel to over come the =E2=80=9Chigh spot=E2=80=9D or resistance=2E<br>I =
have always heard of =E2=80=98inch pounds=E2=80=99 as a measure of torque=
=2E If so, would it not be measured from the center of the steering wheel?<=
br>Lacking a inch pound torque wrench my plan was to hang a one lbs weight =
12 inches from the center of the wheel and make the adjustment until the we=
ight can over come the resistance and falls=2E<br>Is this what you think th=
e author meant?<br>Bob Nogueira<br></blockquote></pre></blockquote></div><b=
r>-- <br>Sent from my Android device with K-9 Mail=2E Please excuse my brev=
ity=2E</body></html>
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[email-masked]

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