Subject: [Healeys] Hot & Cold Brake Wires

From: "R. Lindsay via Healeys" <[email-masked]>
Date: Sun, 11 Jul 2021 16:22:07 -0400

Is there a “hot” or “cold” side to the wiring of the brake switch in a 67 BJ8.  I can see there are two wires to the switch, Green and Green/Purple.  I presume the current enters the switch off of one wire and leaves the switch off the other.  I would guess the current comes to the switch from the green wire and exits via the green/purple, but its only a guess.  Further the “hot” side, I’d guess, is the one that takes the current to the switch (green.)

Is my thinking correct, wrong or neither, i.e., there is no hot or cold side.  Thank you for your input. 

Price Lindsay

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From: "R. Lindsay via Healeys" <[email-masked]>
Date: Sun, 11 Jul 2021 18:38:11 -0400

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Thanks Michael.=20

Price Lindsay

Cell: 630-841-6300
Email: [email-masked]

Sent from my iPhone

> On Jul 11, 2021, at 4:41 PM, Michael Salter <[email-masked]> wrot=
e:
>=20
> =EF=BB=BF
> You are correct.  The live side is the solid green. Live with ignition on.=

>=20
> M
>=20
>> On Sun., Jul. 11, 2021, 4:22 p.m. R. Lindsay via Healeys, <healeys@autox.=
team.net> wrote:
>> Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wi=
ring of the brake switch in a 67 BJ8.  I can see there are two wires to the s=
witch, Green and Green/Purple.  I presume the current enters the switch off o=
f one wire and leaves the switch off the other.  I would guess the current c=
omes to the switch from the green wire and exits via the green/purple, but i=
ts only a guess.  Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess,=
 is the one that takes the current to the switch (green.)
>>=20
>> Is my thinking correct, wrong or neither, i.e., there is no hot or cold s=
ide.  Thank you for your input.=20
>>=20
>>=20
>>=20
>> Archive: http://www.team.net/pipermail/healeys http://autox.team.net/arch=
ive
>>=20
>>=20
>> Unsubscribe/Manage: http://autox.team.net/mailman/options/healeys/michael=
[email-masked]
>>=20

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<html><head><meta http-equiv=3D"content-type" content=3D"text/html; charset=3D=
utf-8"></head><body dir=3D"auto">Thanks Michael.&nbsp;<br><br><div dir=3D"lt=
r">Price Lindsay<div><br></div><div>Cell: 630-841-6300</div><div>Email: 050.=
[email-masked]</div><div><br></div><div>Sent from my iPhone</div></div><div d=
ir=3D"ltr"><br><blockquote type=3D"cite">On Jul 11, 2021, at 4:41 PM, Michae=
l Salter &lt;[email-masked]&gt; wrote:<br><br></blockquote></div><b=
lockquote type=3D"cite"><div dir=3D"ltr">=EF=BB=BF<div dir=3D"auto">You are c=
orrect.&nbsp; The live side is the solid green. Live with ignition on.<div d=
ir=3D"auto"><br></div><div dir=3D"auto">M</div></div><br><div class=3D"gmail=
_quote"><div dir=3D"ltr" class=3D"gmail_attr">On Sun., Jul. 11, 2021, 4:22 p=
.m. R. Lindsay via Healeys, &lt;<a href=3D"mailto:[email-masked]">he=
[email-masked]</a>&gt; wrote:<br></div><blockquote class=3D"gmail_quot=
e" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">I=
s there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wiring=
 of the brake switch in a 67 BJ8.&nbsp; I can see there are two wires to the=
 switch, Green and Green/Purple.&nbsp; I presume the current enters the swit=
ch off of one wire and leaves the switch off the other.&nbsp; I would guess t=
he current comes to the switch from the green wire and exits via the green/p=
urple, but its only a guess.&nbsp; Further the =E2=80=9Chot=E2=80=9D side, I=
=E2=80=99d guess, is the one that takes the current to the switch (green.)<b=
r>
<br>
Is my thinking correct, wrong or neither, i.e., there is no hot or cold side=
.&nbsp; Thank you for your input. <br>
<br>
Price Lindsay<br>
<br>
Sent from my iPad<br>
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