--===============1797622076111580518==
--001a114f0f7245251a05237fe9dd
Although it feels strange, I will beg to differ with Ron: Clearance
is *measured
at the valve*, but you are really setting the clearance *at the cam and
follower*. Because it is not feasible to measure at the cam/follower, if
the rocker ratio is higher you must allow for this and set greater
clearance at the valve to compensate. Stock rockers are 1.25 or 1.3 or
something like that. To correct for 1.5 rockers you should actually
multiply the standard clearance by 1.5/1.25 which is 1.2. 1.2 times12
gives us a corrected clearance of 14.4thou. That said, this is not a
terribly critical setting and depending on the engine build could be a few
thou more.
Hal
On Sat, Oct 31, 2015 at 5:00 PM, Ron Soave via Spridgets <
spridgets@autox.team.net> wrote:
> It doesn't.
>
> Ron Soave
>
> On Oct 31, 2015, at 6:16 PM, Rick Fisk via Spridgets <
> spridgets@autox.team.net> wrote:
>
> Why does increasing the rocker ratio cause a need for more clearance?
>
> Sent from my keyboard
>
> On Oct 31, 2015, at 6:14 PM, Michael Rowe via Spridgets <
> spridgets@autox.team.net> wrote:
>
> I used Minisport roller rockers bought cheap in the 2008-9 crash. I no
> longer remember, but they probably are 1.5 (red), and I also used a "warm"
> Elgin cam that came in a box of parts.
>
> Where higher ratio rockers
> <http://www.spridgetmania.com/part/C-AHT436/Roller-Tipped-15-Ratio-Rockers-Aluminum>
> are
> to be used, the required valve clearance can then be assessed using this
> simple formula. For instance when using 1.5 rockers, you obviously need to
> multiply the cam/follower clearance by 1.5. So 0.010-in x 1.5 gives
> 0.015-in for standard/mild cams and 0.012-in x 1.5 gives 0.018-in for
> race/more-modified cams. Interestingly, most re-profiled performance cams
> generally have a suggested valve clearance of 0.016-in with standard ratio
> rockers. To assess required valve clearance where higher ratio rockers are
> used simply work it backwards and multiply by the higher ratio. This works
> out as 0.016-in divided by 1.25 = 0.0128, then x 1.5 = 0.0192" - or 0.019"
> at the valve.
>
> ----- Original Message -----
> *From:* Michael MacLean <rrengineer.mike@att.net>
> *To:* Rick Fisk <refisk@chartermi.net> ; Michael Rowe
> <mdrowe@optonline.net>
> *Cc:* Spridgets <spridgets@autox.team.net>
> *Sent:* Saturday, October 31, 2015 4:49 PM
> *Subject:* Re: [Spridgets] rocker clearance
>
> How about when you have 1.5 rocker arms? Drove the Bugeye around
> yesterday. Runs great, still blue smoke on acceleration on a recent
> rebuild. At leat 1000 miles since rebuild. I'm afraid the rings never
> seated properly. Not sure of the cylinder wall surface during the rebuild
> as I did not so that part of it.
> Mike MacLean
>
>
>
> On Saturday, October 31, 2015 1:26 PM, Rick Fisk via Spridgets <
> spridgets@autox.team.net> wrote:
>
>
>
> The 0.029 in. spec is a whole different thing used when you are assembling
> the engine. If your engine is together and you just want to set the valve
> clearance it should be 0.012 in. set cold.
>
> Sent from my keyboard
>
> On Oct 31, 2015, at 4:06 PM, Michael Rowe via Spridgets <
> spridgets@autox.team.net> wrote:
>
> New 1275 engine.
> Haynes says "Rocker clearance, timing only = 0.029 in.
> My mechanic/tutor says, "that is twice what it should be."
> Bentley says:
> Rocker clearance: Running (Standard) = 0.012 in. cold
> Running (competition work) = 0.015 in.
> timing = 0.029 in.
> Online sites agree on = .012 in. cold.
>
> So what is the 0.029 in. for?
>
> Michael Rowe
>
> ------------------------
>
> spridgets@autox.team.net
>
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>
--001a114f0f7245251a05237fe9dd
Content-Transfer-Encoding: quoted-printable
<div dir=3D"ltr"><div>Although it feels strange, I will beg to differ with =
Ron:=C2=A0 Clearance is <b>measured at the valve</b>, but you are really se=
tting the clearance <b>at the cam and follower</b>. Because it is not feasi=
ble to measure at the cam/follower, if the rocker ratio is higher you must =
allow for this and set greater clearance at the valve to compensate.=C2=A0 =
Stock rockers are 1.25 or 1.3 or something like that.=C2=A0 To correct for =
1.5 rockers you should actually multiply the standard clearance by 1.5/1.25=
which is 1.2.=C2=A0 1.2 times12 gives us a corrected clearance of 14.4thou=
.=C2=A0 That said, this is not a terribly critical setting and depending on=
the engine build could be a few thou more. =C2=A0 <br></div>Hal<br></div><=
div class=3D"gmail_extra"><br><div class=3D"gmail_quote">On Sat, Oct 31, 20=
15 at 5:00 PM, Ron Soave via Spridgets <span dir=3D"ltr"><<a href=3D"mai=
lto:spridgets@autox.team.net" target=3D"_blank">spridgets@autox.team.net</a=
>></span> wrote:<br><blockquote class=3D"gmail_quote" style=3D"margin:0 =
0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir=3D"auto"><di=
v>It doesn't.=C2=A0<br><br>Ron Soave</div><div><div class=3D"h5"><div><=
br>On Oct 31, 2015, at 6:16 PM, Rick Fisk via Spridgets <<a href=3D"mail=
to:spridgets@autox.team.net" target=3D"_blank">spridgets@autox.team.net</a>=
> wrote:<br><br></div><blockquote type=3D"cite"><div><div>Why does incre=
asing the rocker ratio cause a need for more clearance?<br><br>Sent from my=
keyboard</div><div><br>On Oct 31, 2015, at 6:14 PM, Michael Rowe via Sprid=
gets <<a href=3D"mailto:spridgets@autox.team.net"; target=3D"_blank">spri=
dgets@autox.team.net</a>> wrote:<br><br></div><blockquote type=3D"cite">=
<div>
<div><font face=3D"Arial">I=C2=A0used Minisport roller rockers bought cheap=
in the=20
2008-9 crash.=C2=A0 I no longer remember, but they probably are 1.5=20
(red),=C2=A0and I also=C2=A0used a "warm" Elgin cam that came in =
a box of=20
parts.</font></div>
<div><font face=3D"Arial"></font>=C2=A0</div>
<div><span>Where=C2=A0<a href=3D"http://www.spridgetmania.com/part/C-AHT436=
/Roller-Tipped-15-Ratio-Rockers-Aluminum" target=3D"_blank">higher=20
ratio rockers</a>=C2=A0are to be used, the required valve clearance can the=
n be=20
assessed using this simple formula. For instance when using 1.5 rockers, yo=
u=20
obviously need to multiply the cam/follower clearance by 1.5. So 0.010-in x=
1.5=20
gives 0.015-in for standard/mild cams and 0.012-in x 1.5 gives 0.018-in for=
=20
race/more-modified cams. Interestingly, most re-profiled performance cams=
=20
generally have a suggested valve clearance of 0.016-in with standard ratio=
=20
rockers. To assess required valve clearance where higher ratio rockers are =
used=20
simply work it backwards and multiply by the higher ratio. This works out a=
s=20
0.016-in divided by 1.25 =3D 0.0128, then x 1.5 =3D 0.0192" - or 0.019=
" at the=20
valve.</span></div>
<blockquote style=3D"BORDER-LEFT:#000000 2px solid;PADDING-LEFT:5px;PADDING=
-RIGHT:0px;MARGIN-LEFT:5px;MARGIN-RIGHT:0px" dir=3D"ltr">
<div style=3D"FONT:10pt arial">----- Original Message ----- </div>
<div style=3D"FONT:10pt arial;BACKGROUND:#e4e4e4"><b>From:</b>=20
<a title=3D"rrengineer.mike@att.net" href=3D"mailto:rrengineer.mike@att.n=
et" target=3D"_blank">Michael=20
MacLean</a> </div>
<div style=3D"FONT:10pt arial"><b>To:</b> <a title=3D"refisk@chartermi.ne=
t" href=3D"mailto:refisk@chartermi.net"; target=3D"_blank">Rick Fisk</a> ; <=
a title=3D"mdrowe@optonline.net" href=3D"mailto:mdrowe@optonline.net"; targe=
t=3D"_blank">Michael Rowe</a>=20
</div>
<div style=3D"FONT:10pt arial"><b>Cc:</b> <a title=3D"spridgets@autox.tea=
m.net" href=3D"mailto:spridgets@autox.team.net"; target=3D"_blank">Spridgets=
</a> </div>
<div style=3D"FONT:10pt arial"><b>Sent:</b> Saturday, October 31, 2015 4:=
49=20
PM</div>
<div style=3D"FONT:10pt arial"><b>Subject:</b> Re: [Spridgets] rocker=20
clearance</div>
<div><br></div>
<div style=3D"BACKGROUND-COLOR:#fff;FONT-FAMILY:times new roman,new york,=
times,serif;COLOR:#000;FONT-SIZE:16px">
<div>How about when you have 1.5 rocker=20
arms?=C2=A0 Drove the Bugeye around yesterday.=C2=A0 Runs great, still bl=
ue=20
smoke on acceleration on a recent rebuild.=C2=A0 At leat 1000 miles since=
=20
rebuild.=C2=A0 I'm afraid the rings never seated properly.=C2=A0 Not =
sure of=20
the cylinder wall surface during the rebuild as I did not so that part of=
=20
it.<br></div>
<div dir=3D"ltr">Mike MacLean<br></div>
<div><span></span></div><br>
<div><br><br></div>
<div style=3D"DISPLAY:block">
<div style=3D"FONT-FAMILY:times new roman,new york,times,serif;FONT-SIZE:=
16px">
<div style=3D"FONT-FAMILY:HelveticaNeue,Helvetica Neue,Helvetica,Arial,Lu=
cida Grande,sans-serif;FONT-SIZE:16px">
<div dir=3D"ltr"><font face=3D"Arial" size=3D"2">On Saturday, October 31,=
2015 1:26 PM,=20
Rick Fisk via Spridgets <<a href=3D"mailto:spridgets@autox.team.net"; t=
arget=3D"_blank">spridgets@autox.team.net</a>>=20
wrote:<br></font></div>
<blockquote style=3D"BORDER-LEFT:rgb(16,16,255) 2px solid;MARGIN-TOP:5px;=
PADDING-LEFT:5px;MARGIN-LEFT:5px"><br><br>
<div>
<div>
<div>
<div>The 0.029 in. spec is a whole different thing used when you are=20
assembling the engine.=C2=A0 If your engine is together and you just wa=
nt to=20
set the valve clearance it should be 0.012 in. set cold.<br clear=3D"no=
ne"><br clear=3D"none">Sent from my keyboard</div>
<div>
<div><br clear=3D"none">On Oct 31, 2015, at 4:06 PM, Michael Rowe via S=
pridgets=20
<<a href=3D"mailto:spridgets@autox.team.net"; shape=3D"rect" rel=3D"n=
ofollow" target=3D"_blank">spridgets@autox.team.net</a>>=20
wrote:<br clear=3D"none"><br clear=3D"none"></div>
<blockquote type=3D"cite">
<div></div></blockquote></div></div>
<div>
=20
</div>
<div>
<div>
<div><font face=3D"Arial">New 1275 engine.</font></div>
<div><font face=3D"Arial">Haynes says "Rocker clearance, timing on=
ly=20
=3D=C2=A00.029 in.</font></div>
<div><font face=3D"Arial">My mechanic/tutor says, "that is twice w=
hat it should=20
be."</font></div>
<div><font face=3D"Arial">Bentley says:</font></div>
<div><font face=3D"Arial">Rocker clearance: Running (Standard) =3D 0.01=
2 in.=20
cold</font></div>
<div><font face=3D"Arial">=C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=C2=A0=20
=C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=
=C2=A0=20
=C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=C2=A0 Running (competition work) =3D 0.=
015=20
in.</font></div>
<div><font face=3D"Arial">=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=
=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=20
timing=C2=A0=C2=A0=C2=A0 =C2=A0=C2=A0=C2=A0 =3D 0.029 in.</font></div>
<div><font face=3D"Arial">Online sites=C2=A0agree on=C2=A0 =3D .012 in.=
=20
cold.</font></div>
<div><font face=3D"Arial"></font>=C2=A0</div>
<div><font face=3D"Arial">So what is the 0.029 in. for?</font></div>
<div><font face=3D"Arial"></font>=C2=A0</div>
<div><font face=3D"Arial">Michael Rowe</font></div></div>
<blockquote type=3D"cite">
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</div></blockquote><blockquote type=3D"cite"><div><span>-------------------=
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</div><blockquote type=3D"cite"><div><div><div class=3D"h5"><span>---------=
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