Kids are asleep, Bugeye's running good, wife has a headache, already worked
out - nothing else to do:
A. 60/5 = 12 mph; 60/4 = 15 mph; 60/3 = 20 mph, etc.
B. 1mph = 1.47 ft/sec; @ 3.5 mph walk, that's 5280 ft / hr * 3.5 = 18480
ft / hr = 308 ft / min = 5.13 ft / sec, so about 1.2 seconds.
C. Assume 12 mph "rush" (= very fast run =5min mile) = 12 * 1.47 = 17.64 ft
/ second, 6 feet in .33 seconds
D. Guess: 1.5 mph (less than 1/2 forward walking speed)
E. No clue - I'm a pacifist (who builds warplanes for a living - didn't say
I wasn't a hypocrite)
Momentum, P, = mass * velocity. You have to calculate the ballistics here.
The momentum of the bullet may be high (low mass, but high velocity) in
relation to the person (medium mass, low velocity), and will slow him down.
It also depends on what the bullet hits - not all the momentum will be
transferred to the person if the collision is elastic (ie what the bullet
hits moves, and the bullet exits the body).
Have fun,
Ron
----------
> From: Richard D. Arnold <richard.arnold@juno.com>
> To: mgs@autox.team.net; spridgets@autox.team.net
> Subject: NO LBC -- WAY OFF TOPIC
> Date: Monday, February 09, 1998 8:59 AM
>
> Knowing this is way off topic, I will consider myself flamed in advance.
> Would appreciate the assistance of those with a more scientific mind than
> my own:
>
> Am working on a project for school (an Evidence course). Scenario:
> Driver A shoots Driver B four times during an argument over whether B
> scratched A's MG with a key (semi-LBC content).
>
> Does anyone know:
>
> A. How fast a person is traveling in mph when they travel one mile in
> five, four, three, two, and one minutes? Actually, if someone could just
> tell me the formula for this, I'll figure it myself.
>
> B. How long would it take an average adult person, at a normal pace, to
> cover six feet (in feet per second)? Same thing for the formula....
> Also, how does one convert feet per second into miles per hour?
>
> C. How long would it take an average adult person, rushing, to cover
> six feet (in feet per second)?
>
> D. How fast does an average adult person move backwards (in feet per
> second)?
>
> E. How long (in seconds or fractions thereof) it takes an average adult
> person to fire four shots from a pistol (assuming a double action
> revolver)?
>
> The victim has four wounds that were all inflicted at approximately the
> same distance. The Defendant claims that he fired the shots with a
> slight pause between the first and second. He also claims that the
> victim was approximately six feet away and moving to attack the Defendant
> when the defendant was "forced to fire."
>
> It seems to me that, even if the victim was rushing toward the Defendant,
> and even if the four shots were fired one right after the other, the
> victim would have been in contact with the gun by the time the third shot
> was fired (if for no other reason than momentum would have carried the
> victim forward). If you place a slight pause between the first and
> second shots, it seems to guarantee that the victim would have been in
> contact with the gun when the second, third, and fourth shots (this would
> mean the victim was upright and motionless at the time the shots were
> fired, and thus, no threat).
>
> Those assume the Defendant was not moving backwards. If he was moving
> (since we can't move backwards as quickly as forward), then it still
> seems that the gun would have been in contact with the victim when the
> last shots were fired....
>
> Can anyone offer any advice or assistance with the matematical portions
> of this, and offer a understandable explanation of why it must be so?
>
> Thanks,
>
> Rich
>
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