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Hydraulic pressure (was : Ideas needed......)

To: Mark J Bradakis <mjb@cs.utah.edu>
Subject: Hydraulic pressure (was : Ideas needed......)
From: Randall Young <randallyoung@earthlink.net>
Date: Sat, 06 Jan 2001 09:21:13 -0800
The force exerted by a hydraulic piston  is the area of the piston times
the pressure behind it.  
(Square inches) X (Pounds per Square Inch) = pounds exerted
or
(pounds exerted) / (Square inches) = PSI

The area of the piston is Pi (roughly 3.14 or 22/7) times half the
diameter times half the diameter (aka "Pi R squared").  So, a 2" piston
has an area of 3.14 square inches, while a 3" piston has an area of 3.14
X (3/2) X (3/2) = 7.07 sq in.

24000 pounds divided by 3.14 sq in = 7640 psi
24000 pounds divided by 7.07 sq in = 3390 psi

Randall

Richard White wrote:
> 
> Could you run through how you calulate these values?

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