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Re: [Shop-talk] Inch pounds

To: shop-talk@autox.team.net FTXN9N3opPwlYrTqbk+En0gtnd4XlLBLdwElL+TJGaSlAojBs17w/hWyKfa9UkgtjXCsGcLKY6S2Sw==
Subject: Re: [Shop-talk] Inch pounds
From: neiljsherry--- via Shop-talk <shop-talk@autox.team.net>
Date: Sun, 24 May 2020 21:52:38 +0100
Delivered-to: mharc@autox.team.net
Delivered-to: shop-talk@autox.team.net
References: <B062EF84-08BE-4826-B8E2-7914950363F7@icloud.com> <4a5e50b9-c701-6e4d-479d-50746ab6e445@mebtel.net>
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12 pounds at the rim will be way too much=2E If steering wheel is 15" diame=
ter it will 7=2E5" radius and your 12 pounds will give 90 inch pounds, not =
12!

On 24 May 2020 21:20:31 BST, Eric Russell via Shop-talk <shop-talk@autox=
=2Eteam=2Enet> wrote:
>Maybe a fish scale would give you an approx estimate of 12 lbs pull at=20
>the rim?
>
>On 5/24/2020 2:20 PM, Robert Nogueirao via Shop-talk wrote:
>> Folk I=E2=80=99m  rebuilding a steering box=2E  The manual says to set =
the peg
>thrust adjustment so it takes 12 inch pounds at the rim of the steering
>wheel to over come the =E2=80=9Chigh spot=E2=80=9D or resistance=2E
>> I have always heard of =E2=80=98inch pounds=E2=80=99 as a measure of to=
rque=2E If so,
>would it not be measured from the center of the steering wheel?
>> Lacking a inch pound torque wrench my plan was to hang a one lbs
>weight 12 inches from the center of the wheel and make the adjustment
>until the weight can over come the resistance and falls=2E
>> Is this what you think the author meant?
>> Bob Nogueira
>
>--=20
>Eric Russell
>Mebane, NC
>
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--=20
Sent from my Android device with K-9 Mail=2E Please excuse my brevity=2E
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<html><head></head><body>12 pounds at the rim will be way too much=2E If st=
eering wheel is 15" diameter it will 7=2E5" radius and your 12 pounds will =
give 90 inch pounds, not 12!<br><br><div class=3D"gmail_quote">On 24 May 20=
20 21:20:31 BST, Eric Russell via Shop-talk &lt;shop-talk@autox=2Eteam=2Ene=
t&gt; wrote:<blockquote class=3D"gmail_quote" style=3D"margin: 0pt 0pt 0pt =
0=2E8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">
<pre class=3D"k9mail">Maybe a fish scale would give you an approx estimate=
 of 12 lbs pull at <br>the rim?<br><br>On 5/24/2020 2:20 PM, Robert Nogueir=
ao via Shop-talk wrote:<br><blockquote class=3D"gmail_quote" style=3D"margi=
n: 0pt 0pt 1ex 0=2E8ex; border-left: 1px solid #729fcf; padding-left: 1ex;"=
>Folk I=E2=80=99m  rebuilding a steering box=2E  The manual says to set the=
 peg thrust adjustment so it takes 12 inch pounds at the rim of the steerin=
g wheel to over come the =E2=80=9Chigh spot=E2=80=9D or resistance=2E<br>I =
have always heard of =E2=80=98inch pounds=E2=80=99 as a measure of torque=
=2E If so, would it not be measured from the center of the steering wheel?<=
br>Lacking a inch pound torque wrench my plan was to hang a one lbs weight =
12 inches from the center of the wheel and make the adjustment until the we=
ight can over come the resistance and falls=2E<br>Is this what you think th=
e author meant?<br>Bob Nogueira<br></blockquote></pre></blockquote></div><b=
r>-- <br>Sent from my Android device with K-9 Mail=2E Please excuse my brev=
ity=2E</body></html>
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