Reynolds Numbers

[Elon Ormsby <ormsby1@llnl.gov>]

James Waldron I think your answer is correct but by indicating drag is the 
"cube" of speed might not precisely define the problem.  Isn't drag the 
square of the speed but power required is the cube of the speed? I think 
the additional exponent is for acceleration and power is need for that as 
well as overcoming drag.  I mention this here because many times the 
significance for the "cube" of the power is lost. Many think the power 
required is only to overcome drag (a squaring function) and it ain't so.  I 
look forward to many more of your technically interesting contributions.
    -Elon

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