It would be a lot easier just to add up the amperage of each of the
consumers, and get a total. After all to get the resistance to plug into
your formula you are going to have to know the amperage anyway.
On Sun, Jan 11, 2009 at 12:18 PM, John Trifari <jtrifari@comcast.net> wrote:
> I suppose such a calculation would be nice if in fact every one of the
> items
> in the fuse box are carrying current at the same time. Generally such a
> calculation is not needed since such is not the case. However, those who
> wish to calculate the resistance of a parallel circuit should use the
> following: 1/Rtotal = 1/R1+ 1/R2+ 1/R3 + etc. John Trifari. Golden
> Gate
> Austin Healey Club
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