Thanks!
Matt Murray
----- Original Message -----
From: "Crider, James A." <JamesCrider@metaldyne.com>
To: <mattm@optonline.net>; <autox@autox.team.net>
Sent: Wednesday, November 05, 2003 1:22 PM
Subject: Re: Math problem (triangle area solution)
> On Wed, 05 Nov 2003 10:29:43 -0500, Matt Murray
<mattm@optonline.net> said:
>
> >Okay, we know I am a little thick. :^)
>
> >I gotta triangle that one side is 190, the next side is 125
and the third
> >is 170. How much area do I have?
>
> >I should know this but I am blanking out.
>
> Triangle area is 1/2bh. If 190 is the base, a quick bit of
scaled sketching yields a height of 110, so area is
0.5(190)(110), or 10450 square units. A quick bit of trig says
that the angle between the 190 and 125 sides is 61.64 degrees,
the angle between the 190 and 170 sides is 40.32 degrees, and the
angle between the 170 and 125 sides is 78.04 degrees. Okay, that
last one was easy -- the sum of the three angles in a triangle
must equal 180 degrees, so if you know two of them, the third is
what's left.
>
> This has been today's mathematics lesson. :)
>
> Jim Crider
> autojim@despammed.com
>
>
>
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